5x^2+32x=-28x

Solution for 5x^2+32x=-28x equation:

5x^2+32x=-28x

We move all terms to the left:

5x^2+32x-(-28x)=0

We get rid of parentheses

5x^2+32x+28x=0

We add all the numbers together, and all the variables

5x^2+60x=0

a = 5; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·5·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*5}=\frac{-120}{10}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*5}=\frac{0}{10}
=0
$